| Author |  Topic  |  | 
              
                | Mugless
   
 
                Australia11 Posts
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                      |  Posted - 06/20/2020 :  20:11:07     
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                      | Hi Everyone, 
 Please explain the definition GQ 390 uses for dBm.
 
 I assume the equation of dBm is:
 dBm = 10 * Log10 (P_reading) / (P_reference)
 
 If this is correct, please confirm that P_reference = 100,000 mW/m2, or 10 mW/cm2, since 0 dBm corresponds to that number:
 
 
  
 Thanks,
 Doug
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                | Reply #1 EmfDev
      
 
                2360 Posts | 
                    
                      |  Posted - 06/22/2020 :  09:50:32     
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                      | The RF power reference is 1mW. It is converted to density with other parameters including gain. |  
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                | Reply #2 Mugless
   
 
                Australia11 Posts
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                      |  Posted - 06/22/2020 :  16:00:28     
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                      | Thanks, 
 So the conversion to 1 mW to power density involves a factor of 100,000 that takes into account other parameters including gain.
 Is that the gain of the built-in antenna?
 What are the other parameters?
 Is the 100,000 factor derived from calibration of the GQ 390 against standard, reference equipment? If so, the fact that it is such a neat, round number is odd, if not even suspicious!!
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                | Reply #3 EmfDev
      
 
                2360 Posts | 
                    
                      |  Posted - 06/23/2020 :  10:03:17     
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                      | 0dBm converts to 1mW but in power density becomes 10mW/cm2. 10mW/cm2 converts to 10^5 mW/m2. |  
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